Reduced END Followup

[eepjr24]

Earlier today, you answered this one:

6d6 EB with a +3/4 Advantage and Reduced END: 1/2 END. What is the END cost?
With: 2 End.

I was a bit confused, so I looked at the FAQ, and found this entry:

Question: At what point do you round up to the next
highest number for purposes of calculating END cost? For
example, does a power costing 35 Active Points use 4 END?
Answer: You’d round up at 6 and above. So, 35 costs 3
END; 36 costs 4 END.

And then on pg 173 under Reduced End it says that "...the Power then consumes 1 END per 20 Active Points of Power..."

It seems like the cut off would be 12 for Reduced End? By that logic, it seems like powers with Reduced End would cost 1 END from 1 AP to 31 AP, 2 END until 51 AP, and 3 END at 52 points? I probably have some math wrong, but couldn't figure out what it was.

- Ernie

[Steve Long]

A power with 52 Active Points costs 5 END. Half of 5 is 2.5, which rounds down to 2. The Advantage is specifically described as "reduc[ing] the normal END cost of a Power"; the text does not say "halve the Power's Active Points for purposes of calculating END."