END cost for FTL travel

[Crypt]

When dealing with characters or vehicles (ship) with FTL travel and a Cost END limitation, assuming a cruising SPD 2 we may use existing parameters (VF and Range mod) to quickly find the END/Fuel cost of a long trip =

Velocity Factor of light is 54. (cf APG p 178)
Because FTL travel follows the same scale as VF we can say that : the VF of FTL equals Base Cost+44.
10 pts = VF 54
56 pts= VF 100
60 pts = VF 104, etc.

Now find the Range mod of the distance travelled.
1UA=Range mod 68
1 Light Year = Range mod 100. (cf 6E2p 162)

Let's say e=END cost per phase.

Total END cost = [(√2)^(Range-VF)] * 2/3 * e.

For instance:
at 10 pts of FTL (light speed); Cost End (-1/2) : 1 END/phase
we want to travel 1 light year
VF=54
Range=100
Total END cost = [(√2)^(100-54)] * 2/3 * 1 = 5 million END.


at 56 pts of FTL (light speedX8M); Cost End (-1/2) : 6 END/phase
we want to travel 1 light year
VF=100
Range=100
Total END cost = [(√2)^(100-100)] * 2/3 * 6 = 4 END


at 12 pts of FTL (light speedX2); Cost End (-1/2) Increased End Cost X10 (-4) : 10 END/phase
we want to travel 1 UA
VF=56
Range=68
Total END cost = [(√2)^(68-56)] * 2/3 * 10 = 427 END


Obviously it could be a table instead of an equation =
http://cryptmaster.free.fr/site/HERO/FTL.php

[Crypt]

In order to find the time required =

Time = Range - VF.

Then check this table:

-4=1seconds
-2=2 sec
0=4 sec
2=8 sec
4=15 sec
6=30 sec
8=1minute
10=2mn
12=4mn
14=8mn
16=16mn
18=32mn
20=1hour
22=2h
24=4h
26=8h
28=16h
30=32h
32=64h
34=128h
36=256h
38=512h
40=1024h
42=3 months
44=6 months
46=1 year
etc.

Ex:
1UA (68) at light speed (54) = 68-54 = 14 = 8 minutes

As far as you use VF this table works with any movement power.

The actual formulae is=
Time in seconds = [(√2)^(Range-VF)]X[(60X60X24X365)/[(√2)^46]]