Calculating AUs for 10 planets - with an AI

[GoldenAge]

So, I had hunkered down to flesh out a few solar systems for my Star Hero game (based on the Alien Legion comic book) and, being an artist, was not excited about the math... Then it dawned on me - It's 2024 and AI is REAL!!! I then rushed to my new best campaign creation tool and asked it for help...

This took Chat GPT less than 30 seconds (note that ChatGPT inferred that I was talking about AUs and added it to its answers):


 

ME: Determine orbital distances for 10 planets by rolling 1d6 divided by 10, then multiplying by 1 + (2d6/10) for each subsequent planet.

ChatGPT

To help you with this task, I'll simulate rolling the dice and calculate the orbital distances for each of the 10 planets according to the given formula. Let's start with the first planet and work our way to the tenth.

For each planet:

1. Roll a 1d6 (one six-sided die), divide the result by 10.
2. Then roll 2d6 (two six-sided dice), divide the total by 10, add 1 to it, and multiply it with the result from step 1.

Planet 1

• 1d6 roll: 4
• Orbital distance = 4 / 10 = 0.4 AU (Astronomical Units)

Now, for the subsequent planets, I will apply the formula using the new rolls.

Planet 2

• 1d6 roll for the base distance = 0.4 (from Planet 1)
• 2d6 roll = 8 (for example, 3 + 5)
• New factor = 1 + (8 / 10) = 1.8
• Orbital distance = 0.4 * 1.8 = 0.72 AU

Planet 3

• 1d6 roll for the base distance = 0.72 (from Planet 2)
• 2d6 roll = 7 (for example, 4 + 3)
• New factor = 1 + (7 / 10) = 1.7
• Orbital distance = 0.72 * 1.7 = 1.224 AU

Continuing this pattern:

Planet 4

• 2d6 roll = 9 (for example, 5 + 4)
• New factor = 1 + (9 / 10) = 1.9
• Orbital distance = 1.224 * 1.9 = 2.3256 AU

Planet 5

• 2d6 roll = 6 (for example, 3 + 3)
• New factor = 1 + (6 / 10) = 1.6
• Orbital distance = 2.3256 * 1.6 = 3.72096 AU

Planet 6

• 2d6 roll = 11 (for example, 6 + 5)
• New factor = 1 + (11 / 10) = 2.1
• Orbital distance = 3.72096 * 2.1 = 7.814016 AU

Planet 7

• 2d6 roll = 5 (for example, 2 + 3)
• New factor = 1 + (5 / 10) = 1.5
• Orbital distance = 7.814016 * 1.5 = 11.721024 AU

Planet 8

• 2d6 roll = 12 (for example, 6 + 6)
• New factor = 1 + (12 / 10) = 2.2
• Orbital distance = 11.721024 * 2.2 = 25.7862528 AU

Planet 9

• 2d6 roll = 4 (for example, 2 + 2)
• New factor = 1 + (4 / 10) = 1.4
• Orbital distance = 25.7862528 * 1.4 = 36.100754 AU

Planet 10

• 2d6 roll = 10 (for example, 5 + 5)
• New factor = 1 + (10 / 10) = 2
• Orbital distance = 36.100754 * 2 = 72.201508 AU

Note: The actual values for each planet's orbital distance will vary because the rolls of 2d6 are hypothetical in this calculation. To determine the exact distances for your scenario, you would need to roll the dice for each step as described.

Awesome!