### Discussion :: Strength of Materials - Section 1 (Q.No.37)

Nikhil said: (Nov 17, 2013) | |

Where N = The speed in r.p.m. T = the torque in kgm. Therefore, P=2*(py)*N*T/4500. Where (py) is 3.141. |

Bhavsingh said: (Oct 26, 2015) | |

p = 2*(py)*n*T/4500. T = 150 kgm. n = 150 r.p.m. p = 10*(py). |

Monika said: (Apr 19, 2016) | |

p = 2nNT/4500. N = 150 rpm. T = 150 kgm. p = 10n. |

Akhilandeshwari said: (Aug 26, 2016) | |

P = 2 * φ * N * T/4500, P = 2 * φ * 150 * 150/4500, p = 10 *φ. |

Krishna Murti said: (Mar 14, 2017) | |

How 4500 come? Anybody, Kindly explain it. |

Raghuraj Singh Chauhan said: (Mar 16, 2017) | |

1 horse power = 745.6998 watts, then we find the answer. |

Venkatramana G said: (Sep 3, 2017) | |

1HP=745.699watts then 2πN/60 x 1/745.699 gives 2πNT/45000 how 4500 comes? |

Shiva said: (Sep 23, 2017) | |

P = 2πNT/4500. We get p=31.41, Which is equal to 10π. |

Sachin said: (Oct 14, 2017) | |

@Venkat. T is in kg-m, so convert it to Newton by multiplying 10m/s^2. You will get 4500. |

Prasenjit said: (Jan 2, 2018) | |

2πNT/4500. |

Ruchir said: (May 5, 2018) | |

P = 2πNT/60. P = 2*π*150*150*10/60*746watt. = 10π. |

Rakesh said: (Jun 5, 2018) | |

2πNT/45000. Because 1hp =746watt. Then you will get 10π. |

Koushik said: (Sep 10, 2018) | |

Work done per second = 2πNT/60KNm. N=RPM. T=Torque in KNm. |

Rashid said: (Apr 3, 2020) | |

Power = 2πNT/60 ( in watts) = 2πNT/(60*746) (in HP). N = 150 r.p.m. T = 150 Kgm = 150*10Nm = 1500Nm (1kg = 10N approx). After putting all value in the equation you will get, Ans : 10π. |

Parth said: (Aug 5, 2020) | |

1 kg = 9.81N. Power = angular velocity x torque x 9.81 watts. |

Tanmoy Ghosh said: (Jan 3, 2021) | |

2π*N*T/4500, 10π. |

Mjm Gcek said: (Aug 17, 2021) | |

You Solved it clearly, Thanks @Rashid. |

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