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DavidToomey

HERO Member
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About DavidToomey

  • Birthday 01/30/1963

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  • Occupation
    Restaurant Manager

DavidToomey's Achievements

  1. Re: Omcv 1? Boy... toss out one quick question, work 6 days straight, and see what happens... I really wasn't trying to cause *this* much activity:rolleyes: And yes, I did type OMCV in the title...darn formatting
  2. I've looked through the books, and see no penalty for someone selling back his OMCV to 1 if he has no abilities that require a MCV to hit roll. Am I missing something, or is this an easy 6 points for 90+ % of charactrers?
  3. Re: Lifetime Subscription Strategy & Tactics? Hail and well met, fellow grognard!
  4. Re: Do you have any "deal breakers" when it comes 6th edition? Is one of them a pair of hot lesbians...? ...or is that particular poster long gone?
  5. Re: Would you allow a BODY Aid to work on an Entangle? I don't have Fred handy, but isn't +1 Body Entangle cost 5 pts, not 2? Plus, you would probably want to boost the fade rate a bit...
  6. Re: Intermediate levels of +5 = x2 I'm not sure why you'd need the formula in HD...a custom adder (3x copies) 8 pts looks like it would work just fine, or am I not understanding? Dave T
  7. Has anyone done (or seen) Hero System Writeups for any of the characters from the TV series VERONICA MARS?
  8. Re: Putting my finger on it I'd buy that in a heartbeat, though I think I've seen far too many munchkin constructs in the years I've played since 1st Ed Of course, what's abuse in one game may be just right under another GM. ...darn kids! get outta my 5thRevised!...
  9. Re: Tum, Tum, Tum! I thought we were trying to work out chewable Antacids as a power: TUMS,TUMS,TUMS...
  10. Re: The Genesis of +5 = 2x power? Sorry, but no. My formula *is* correct, and it is derived from the Strength Lifting formula, using # of dice instead of (Str/5) The continued doubling per 5 pts is logrithmic, where your formula is arithmatic. By yours: 1d6 =(1*2)-1=1 2d6 =(2*2)-1=3 3d6 =(3*2)-1=5 If you want the number of units you need to generate xd6, where 1 unit does yd6, the formula is: Units = 2^(x-y) If you want to know how many d6 U units will generate when one unit does yd6...whew...: Xd6=(Log(base2) U) +y , where you have at least 2 units (as 1 unit = yd6) so, if 1 unit does 2d6 2 units=Log(2) 2 units + 2= 1+2=3d6 4 units=Log(2) 4 units + 2= 2+2=4d6 8 units=Log(2) 8 units + 2= 3+2=5d6 Calc Hero, anybody?
  11. Re: The Genesis of +5 = 2x power? No, the final power = 2 to the power of (number of dice rolled-1) Thus 1d6 = 2^(1-1)=1 2d6 = 2^(2-1)=2 3d6 = 2^(3-1)=4 4d6 = 2^(4-1)=8 ... Thus in theory, you'd have to strap (8) 1d6 explosives together to get the same effect as (1) 4d6 explosive. ...not that hero 5th has been using that system anymore (look at their explosives chart)
  12. Re: A variant of standard effect damage How about using margin of success? Add one or two points of damage per point you made your to hit by...thus that 15- who rolled a 5 does 10 or 20 extra damage, where if he rolled 15 exactly, he just barely hit, thus no bonus damage...
  13. Re: A variant of standard effect damage So, the better your roll to hit, the less damage you do? If I read this right, if you can hit on a 15- and you roll 15, you do 10 pts *more* damage than if you roll a 5....
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