GoldenAge

Crew size = # of Players you can competently handle. Everything else is fairly arbitrary.

A ship can run with a captain or a group of likeminded crew members. It can run with a Ship's Engineer or an entire Engineering team including a Chief Engineer, a Propulsion Expert, an Electrician, and more.
The ship may have a single Pilot, or operation of the ship can be broken down into an entire bridge crew including a Captain, a Helmsman, a Navigator, a Stellar Cartographer, Sensor Operations, Science Officer, Weapons Specialist, Gunner, etc, etc...etc.

Premade templates in 6th Edition are limited, but one look at all the 5E products (Terran Empire, Aliens Wars, Spacer's Toolkit, and secondary publications like Star Trek HERO – Unofficial Resource Guide and Battlestar Galactica Hero By Richard Littles - all of which are easily adaptable to 6E) and you'll find dozens of crew templates and package deals.

Mostly, it's whatever you think is fun!
 
 
In our current game we have a Captain, Helmsman, Navigator, Engineer, Sensor Operations, Ships Weapons Chief and 2 utility NPC; another engineer and a gambling, streetwise, appraisal and trade expert.

Crew size = # of Players you can competently handle. Everything else is fairly arbitrary.

A ship can run with a captain or a group of likeminded crew members. It can run with a Ship's Engineer or an entire Engineering team including a Chief Engineer, a Propulsion Expert, an Electrician, and more.
The ship may have a single Pilot, or operation of the ship can be broken down into an entire bridge crew including a Captain, a Helmsman, a Navigator, a Stellar Cartographer, Sensor Operations, Science Officer, Weapons Specialist, Gunner, etc, etc...etc.

Premade templates in 6th Edition are limited, but one look at all the 5E products (Terran Empire, Aliens Wars, Spacer's Toolkit, and secondary publications like Star Trek HERO – Unofficial Resource Guide and Battlestar Galactica Hero By Richard Littles - all of which are easily adaptable to 6E) and you'll find dozens of crew templates and package deals.

Mostly, it's whatever you think is fun!
 
 
In our current game we have a Captain, Helmsman, Navigator, Engineer, Sensor Operations, Ships Weapons Chief and 2 utility NPC; another engineer and a gambling, streetwise, appraisal and trade expert.

THere was one small, little detail I forgot to mention in my list of things a ship's Captain would have to accomplish to make the cross galaxy trip. Refeuling, the ship that is, one assumes they have enough storage for at least 3 months of consumables onboard. So, at least 12 to 18 months to make the voyage.

If you keep the Teleport and Megascale as is in the OP but up your cyclic rate to one jump an hour, you can travel 4800 lightyears a day.
 
If you want to keep the cyclic rate at six jumps per day, you'd need 80 meters of Teleport at 10 lightyears of Megascale to get the same result.

Right, its got to be fast enough that moving to nearby systems doesn't require hibernation, but long enough that there is some drama and tension.  If you can call home from 240000 light years and talk in real time, it damages the sense of distance, isolation, danger, and real adventure.  Done properly it can feel like old ships exploring and traveling.  There's adventure in the trip, but they are so alone they don't get news for weeks or months.  There's no rescue gonna come hyperspace in like the cosmic cavalry.

True Mr. Taylor true. At the same time you don't want to take so much time moving from star "A" to star "B" that your players lose focus and intrest.

This is the level of tech I prefer to be roughly max for sci fi settings.  You don't want it to be a fast travel cut scene to get from one end of a galaxy to another, the distances and remoteness are a key part of the genre.

Marcus is correct, it will take 2000 hours to cross the galaxy assuming the 100,000 LY width. 2000 hours = 83,3 days or just shy of the 3 months. In actuality it will probably take at least twice that, refueling, eating, sleeping and general maintainence on the vessel will extend the trip to a year to 18 months. You will have to achieve my short list of tasks to complete this goal, mainly sleeping. It has been a very long time since I pulled an all nighter, back then I went "5 days" without sleep during exam week, the end result was not pretty.

More like 20 meters times ten lightyears times six times a day equals one thousand two hundred lightyears a day, so crossing the galaxy takes three months.

It can cycle 6 times a day, for 10ly each, so 60 ly a day assuming it has the END. 
 
According to my trusty calculator, it'll take (100,000/60) 1666 and 2/3 days.

I don't think you need to, now.
 
Did the old post get stuck in a buffer, or something?

Fixed
 
 
 

You asked this very question just recently, and it was answered.

Obviously, this is a trap designed to capture Kate Upton in zero gravity.
 
In a bikini.
 
I will donate many character points to this endeavor.

I could share what I have for my campaigns, which has some mock-ups of some popular sci-fi weapons (types, not specifics, generally.)
 
https://www.dropbox.com/s/r3qf47ek11r2hr2/SSttR General Prefabs.hdp?dl=0
 
It has a few errors and some atypical stuff, so "your results may vary." 

Here are some from this site:
 
https://www.herogames.com/forums/files/file/294-pulsed-energy-projectile-weapons/
 
https://www.herogames.com/forums/files/file/127-sh-phasors/
 
https://www.herogames.com/forums/files/file/193-star-hero-kazei-5-cybernetic-implants/
 
https://www.herogames.com/forums/files/file/236-traveller-hero-tl10-tl15-battle-dress/
 
https://www.herogames.com/forums/files/file/246-warhammer-40k-hero-space-marine-implants/
 
https://www.herogames.com/forums/files/file/247-warhammer-40k-hero-space-marine-power-armour-mark-vii/
 
https://www.herogames.com/forums/files/file/248-warhammer-40k-hero-space-marine-power-armour-terminator/

I think you missed a step or two there.
 
First you have to buy your butler as a Follower.
 
Then the butler buys the Galactica, then the Galactica buys its Vipers, then the Vipers buy their pilots as followers.

So, I had hunkered down to flesh out a few solar systems for my Star Hero game (based on the Alien Legion comic book) and, being an artist, was not excited about the math... Then it dawned on me - It's 2024 and AI is REAL!!! I then rushed to my new best campaign creation tool and asked it for help...

This took Chat GPT less than 30 seconds (note that ChatGPT inferred that I was talking about AUs and added it to its answers):


 
ME: Determine orbital distances for 10 planets by rolling 1d6 divided by 10, then multiplying by 1 + (2d6/10) for each subsequent planet.
ChatGPT To help you with this task, I'll simulate rolling the dice and calculate the orbital distances for each of the 10 planets according to the given formula. Let's start with the first planet and work our way to the tenth.
For each planet:
Roll a 1d6 (one six-sided die), divide the result by 10. Then roll 2d6 (two six-sided dice), divide the total by 10, add 1 to it, and multiply it with the result from step 1. Planet 1
1d6 roll: 4 Orbital distance = 4 / 10 = 0.4 AU (Astronomical Units) Now, for the subsequent planets, I will apply the formula using the new rolls.
Planet 2
1d6 roll for the base distance = 0.4 (from Planet 1) 2d6 roll = 8 (for example, 3 + 5) New factor = 1 + (8 / 10) = 1.8 Orbital distance = 0.4 * 1.8 = 0.72 AU Planet 3
1d6 roll for the base distance = 0.72 (from Planet 2) 2d6 roll = 7 (for example, 4 + 3) New factor = 1 + (7 / 10) = 1.7 Orbital distance = 0.72 * 1.7 = 1.224 AU Continuing this pattern:
Planet 4
2d6 roll = 9 (for example, 5 + 4) New factor = 1 + (9 / 10) = 1.9 Orbital distance = 1.224 * 1.9 = 2.3256 AU Planet 5
2d6 roll = 6 (for example, 3 + 3) New factor = 1 + (6 / 10) = 1.6 Orbital distance = 2.3256 * 1.6 = 3.72096 AU Planet 6
2d6 roll = 11 (for example, 6 + 5) New factor = 1 + (11 / 10) = 2.1 Orbital distance = 3.72096 * 2.1 = 7.814016 AU Planet 7
2d6 roll = 5 (for example, 2 + 3) New factor = 1 + (5 / 10) = 1.5 Orbital distance = 7.814016 * 1.5 = 11.721024 AU Planet 8
2d6 roll = 12 (for example, 6 + 6) New factor = 1 + (12 / 10) = 2.2 Orbital distance = 11.721024 * 2.2 = 25.7862528 AU Planet 9
2d6 roll = 4 (for example, 2 + 2) New factor = 1 + (4 / 10) = 1.4 Orbital distance = 25.7862528 * 1.4 = 36.100754 AU Planet 10
2d6 roll = 10 (for example, 5 + 5) New factor = 1 + (10 / 10) = 2 Orbital distance = 36.100754 * 2 = 72.201508 AU Note: The actual values for each planet's orbital distance will vary because the rolls of 2d6 are hypothetical in this calculation. To determine the exact distances for your scenario, you would need to roll the dice for each step as described.

Awesome!

So, I had hunkered down to flesh out a few solar systems for my Star Hero game (based on the Alien Legion comic book) and, being an artist, was not excited about the math... Then it dawned on me - It's 2024 and AI is REAL!!! I then rushed to my new best campaign creation tool and asked it for help...

This took Chat GPT less than 30 seconds (note that ChatGPT inferred that I was talking about AUs and added it to its answers):


 
ME: Determine orbital distances for 10 planets by rolling 1d6 divided by 10, then multiplying by 1 + (2d6/10) for each subsequent planet.
ChatGPT To help you with this task, I'll simulate rolling the dice and calculate the orbital distances for each of the 10 planets according to the given formula. Let's start with the first planet and work our way to the tenth.
For each planet:
Roll a 1d6 (one six-sided die), divide the result by 10. Then roll 2d6 (two six-sided dice), divide the total by 10, add 1 to it, and multiply it with the result from step 1. Planet 1
1d6 roll: 4 Orbital distance = 4 / 10 = 0.4 AU (Astronomical Units) Now, for the subsequent planets, I will apply the formula using the new rolls.
Planet 2
1d6 roll for the base distance = 0.4 (from Planet 1) 2d6 roll = 8 (for example, 3 + 5) New factor = 1 + (8 / 10) = 1.8 Orbital distance = 0.4 * 1.8 = 0.72 AU Planet 3
1d6 roll for the base distance = 0.72 (from Planet 2) 2d6 roll = 7 (for example, 4 + 3) New factor = 1 + (7 / 10) = 1.7 Orbital distance = 0.72 * 1.7 = 1.224 AU Continuing this pattern:
Planet 4
2d6 roll = 9 (for example, 5 + 4) New factor = 1 + (9 / 10) = 1.9 Orbital distance = 1.224 * 1.9 = 2.3256 AU Planet 5
2d6 roll = 6 (for example, 3 + 3) New factor = 1 + (6 / 10) = 1.6 Orbital distance = 2.3256 * 1.6 = 3.72096 AU Planet 6
2d6 roll = 11 (for example, 6 + 5) New factor = 1 + (11 / 10) = 2.1 Orbital distance = 3.72096 * 2.1 = 7.814016 AU Planet 7
2d6 roll = 5 (for example, 2 + 3) New factor = 1 + (5 / 10) = 1.5 Orbital distance = 7.814016 * 1.5 = 11.721024 AU Planet 8
2d6 roll = 12 (for example, 6 + 6) New factor = 1 + (12 / 10) = 2.2 Orbital distance = 11.721024 * 2.2 = 25.7862528 AU Planet 9
2d6 roll = 4 (for example, 2 + 2) New factor = 1 + (4 / 10) = 1.4 Orbital distance = 25.7862528 * 1.4 = 36.100754 AU Planet 10
2d6 roll = 10 (for example, 5 + 5) New factor = 1 + (10 / 10) = 2 Orbital distance = 36.100754 * 2 = 72.201508 AU Note: The actual values for each planet's orbital distance will vary because the rolls of 2d6 are hypothetical in this calculation. To determine the exact distances for your scenario, you would need to roll the dice for each step as described.

Awesome!

I found some old Savage Worlds conversions of Mass Effect and Star Wars that will be helpful!
https://docs.google.com/document/d/1XI3CEzxO1qcGY5A3Zaya4_-tyJEp5EJZpWxtpaskNkM/edit
 

Well, there used to be a lot of fan conversions on the Web for 4E/5E, but most of those have disappeared. One can often find at least parts of the old sites via the Internet Archive Wayback Machine, if one can unearth the original links.
 
I'm trying to untangle some of those old links now, but it will take some time. But for now, I can start with packages for some of Babylon 5's races, from Aroooo's grand old Star HERO Fandom website: https://web.archive.org/web/20060908090629/http://www.starherofandom.com/b5/packages.php
 
And here's a website with packages for Star Wars races: https://web.archive.org/web/20071012104303/http://www.sysabend.org/champions/campaigns/StarHeroWars/CharacterGeneration.htm
 
I'll work on putting up more links as time permits.

Update: The battle went well - I kept their original defenses, their only limitation was a singleminded approach towards attacking "themselves) - eliminating the many bonuses that come from tactics and multiple attackers)
Epic Alliance were on their heels for a moment, then got their bearings and strategy together. The castled to take advantage of the doppelgängers enraged state, they englobed with Barrier, entangled, grabbed and blinded their doppelgängers - The ultimate result was multiple called shot heads against entangled or bind opponents. Epic Alliance overcame the problem in shining fashion.

It was very interesting watching them overcome their codes against killing and utilize their powers in new ways.

Thanks all!!!

Update: The battle went well - I kept their original defenses, their only limitation was a singleminded approach towards attacking "themselves) - eliminating the many bonuses that come from tactics and multiple attackers)
Epic Alliance were on their heels for a moment, then got their bearings and strategy together. The castled to take advantage of the doppelgängers enraged state, they englobed with Barrier, entangled, grabbed and blinded their doppelgängers - The ultimate result was multiple called shot heads against entangled or bind opponents. Epic Alliance overcame the problem in shining fashion.

It was very interesting watching them overcome their codes against killing and utilize their powers in new ways.

Thanks all!!!

That is presuming that they aren't falling onto broken ground, sharp edges. 🙂
 
I would be looking to find ways of dropping, pushing, pulling the doppelgangers onto sharp/edged surfaces.  Change velocity into killing damage.

Hugh's post just doubles down on my original question. Normally, the Takes No Stun Power triples the cost of Resistant PD/ED. Will the doppelgangers have full value, or will they be reduced? This is going to be the biggest factor in determining strategy.