Character Creation help

[Malkav]

So while I am not entirely new to HERO, I have not played since 1993. So 6E is new to me and I have forgotten much of the crunch from back then.

 

What I am wondering is how power costs (in character points) are actually calculated. I have read the first book and could not find this explained. There are lots of examples but they dont make sense using math. IE 40 +1/2 is not 60 normally. It would be 40.5 or rounded 41. I'm really confused and the rounding paragraph was even more wonky. Why on earth would you round 1 1/4 to 3/4? That is just way over my head. Really this game needs a chapter outlining how to do the math. It would also be nice to have an exact list of costs when it comes to each modifier that can be applied instead of having to hunt them down in examples hidden throughout the book.

[Steve Long]

I'm sorry, but I don't answer game design/philosophy questions.

 

However, I can explain one thing where you're overlooking something in the rules. a 40-point power with a +1/2 Advantage isn't 40 + 1/2 = 40.5. As explained on 6E1 313, it's 40 x (1 + 1/2), = 60. The +1/2 is a form of notation, it's not a literal indication to add the value of the Advantage to the value of the power.

 

If you have other general questions or concerns where the math's not making sense to you, I'd suggest posting on the Discussion board. Anyone can answer there (not just me) and you'll get a fast response.