Suppose one has a Naked Advantage that is a group Naked Advantage (ie limited by active points, not tied to a specific power), can that Naked Advantage then be used twice, once to give its advantage to Str, and once again to give its advantage to HTH attack by paying its END cost twice so as to let you add the Damage Dice together without qualifier since both the STR and HTH will then have the advantage?
Example:
40 Str, 40 Active, 4 END
HTH Attack 8d6, 40 Active, 4 END
Naked Advantage 1.5x Knockback for upto 40 Active Points (Group type Naked Advantage), 20 Active, 20 Real, 2 END
So can you pay 2x2 = 4 END to use the Naked Advantage twice, once for STR and once for HTH to allow you to attack for 16d6 with 1.5x Knockback after paying and additional 4 END for Str and 4 more END for HTH for a total of 12 END?
There is question in the FAQ that confuses me a bit, because it gives the example of a Naked Advantage to HTH and states that Damage cant total higher then the Active Points that the Naked Advantage can cover. Which seems a bit strange because that would mean it was a group naked advantage, not a naked advantage limited just to HTH, which doesnt go by active points, it is determined at its creation.
If the example in the FAQ is how it also applies to group naked advantages, then the results are very different from just having an advantaged HTH attack and using the STR Damage stacking rules for them (ie able to add upto the base unadvantaged active points of the HTH attack in STR). Im not sure of this is intentional or a byproduct of the fact that HTH should be viewed as limited STR. If HTH should be viewed a seperate power then I would think after paying the END on the naked advantage to give your HTH an advantage, the damage stacking rules should be the same as if the HTH attack had the advantage in the first place, but it seems they are not.
Question
mmshah
Suppose one has a Naked Advantage that is a group Naked Advantage (ie limited by active points, not tied to a specific power), can that Naked Advantage then be used twice, once to give its advantage to Str, and once again to give its advantage to HTH attack by paying its END cost twice so as to let you add the Damage Dice together without qualifier since both the STR and HTH will then have the advantage?
Example:
40 Str, 40 Active, 4 END
HTH Attack 8d6, 40 Active, 4 END
Naked Advantage 1.5x Knockback for upto 40 Active Points (Group type Naked Advantage), 20 Active, 20 Real, 2 END
So can you pay 2x2 = 4 END to use the Naked Advantage twice, once for STR and once for HTH to allow you to attack for 16d6 with 1.5x Knockback after paying and additional 4 END for Str and 4 more END for HTH for a total of 12 END?
There is question in the FAQ that confuses me a bit, because it gives the example of a Naked Advantage to HTH and states that Damage cant total higher then the Active Points that the Naked Advantage can cover. Which seems a bit strange because that would mean it was a group naked advantage, not a naked advantage limited just to HTH, which doesnt go by active points, it is determined at its creation.
If the example in the FAQ is how it also applies to group naked advantages, then the results are very different from just having an advantaged HTH attack and using the STR Damage stacking rules for them (ie able to add upto the base unadvantaged active points of the HTH attack in STR). Im not sure of this is intentional or a byproduct of the fact that HTH should be viewed as limited STR. If HTH should be viewed a seperate power then I would think after paying the END on the naked advantage to give your HTH an advantage, the damage stacking rules should be the same as if the HTH attack had the advantage in the first place, but it seems they are not.
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