END cost for FTL travel

[Crypt]

When dealing with characters or vehicles (ship) with FTL travel and a Cost END limitation, assuming a cruising SPD 2 we may use existing parameters (VF and Range mod) to quickly find the END/Fuel cost of a long trip =

 

Velocity Factor of light is 54. (cf APG p 178)

Because FTL travel follows the same scale as VF we can say that : the VF of FTL equals Base Cost+44.

10 pts = VF 54

56 pts= VF 100

60 pts = VF 104, etc.

 

Now find the Range mod of the distance travelled.

1UA=Range mod 68

1 Light Year = Range mod 100. (cf 6E2p 162)

 

Let's say e=END cost per phase.

 

Total END cost = [(√2)^(Range-VF)] * 2/3 * e.

 

For instance:

at 10 pts of FTL (light speed); Cost End (-1/2) : 1 END/phase

we want to travel 1 light year

VF=54

Range=100

Total END cost = [(√2)^(100-54)] * 2/3 * 1 = 5 million END.

 

 

at 56 pts of FTL (light speedX8M); Cost End (-1/2) : 6 END/phase

we want to travel 1 light year

VF=100

Range=100

Total END cost = [(√2)^(100-100)] * 2/3 * 6 = 4 END

 

 

at 12 pts of FTL (light speedX2); Cost End (-1/2) Increased End Cost X10 (-4) : 10 END/phase

we want to travel 1 UA

VF=56

Range=68

Total END cost = [(√2)^(68-56)] * 2/3 * 10 = 427 END

 

 

Obviously it could be a table instead of an equation =

http://cryptmaster.free.fr/site/HERO/FTL.php

[Crypt]

Re: END cost for FTL travel

 

In order to find the time required =

 

Time = Range - VF.

 

Then check this table:

 

-4=1seconds

-2=2 sec

0=4 sec

2=8 sec

4=15 sec

6=30 sec

8=1minute

10=2mn

12=4mn

14=8mn

16=16mn

18=32mn

20=1hour

22=2h

24=4h

26=8h

28=16h

30=32h

32=64h

34=128h

36=256h

38=512h

40=1024h

42=3 months

44=6 months

46=1 year

etc.

 

Ex:

1UA (68) at light speed (54) = 68-54 = 14 = 8 minutes

 

As far as you use VF this table works with any movement power.

 

The actual formulae is=

Time in seconds = [(√2)^(Range-VF)]X[(60X60X24X365)/[(√2)^46]]