Mr. Long, According to page 113 Star Hero, you calculate the lessening of earths gravity due to centrifugal effects to be less by .0009%, however I cannot get the numbers to come out correctly... could you assist? Here is what I calculated... The formula would be [(Mass^.333*500)/(3600*Radius)]^2.... Which according to my calculations works out like this: If Earth's Mass is 1, and the period of rotation is 24 hours, then this is [(1^.333*500)/(3600*24)]^2 = (.005787)^2= .000033, not the .000009 as listed.... what am I missing?
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shuddemell
Mr. Long, According to page 113 Star Hero, you calculate the lessening of earths gravity due to centrifugal effects to be less by .0009%, however I cannot get the numbers to come out correctly... could you assist? Here is what I calculated... The formula would be [(Mass^.333*500)/(3600*Radius)]^2.... Which according to my calculations works out like this: If Earth's Mass is 1, and the period of rotation is 24 hours, then this is [(1^.333*500)/(3600*24)]^2 = (.005787)^2= .000033, not the .000009 as listed.... what am I missing?
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